THEOREM D: If J is any simple closed curve and T is any triangle then J has an inscribed triangle similar to T.
Proof: The proof takes place in five steps.
Step 2. Let X be a point where this circle first touches J (there may be more than one such point). Inscribe a triangle XYZ in the circle so that XYZ is similar to T and YZ is a longest side. (Note that any triangle can be inscribed in a circle.) Now move Y and Z away from X proportionally (so that XYZ is similar to T at all times). Stop the motion when one of them first touches the curve J.
Step 4. Once X is moved to P, begin moving Y along the curve toward Q, again moving Z to preserve the similarity class of XYZ.
Note: This is a truly pretty proof, but it merely shows there must be such a triangle somewhere. It really doesn't tell you where that triangle will occur, and using this method to actually find the triangle would be very difficult because of the simultaneous motion of points it requires. But Theorem E will show us that no matter where we are on the curve J, we wouldn't have to move far to find a vertex of one of our inscribed triangles.